Make buildExportAll generate pure ES5 code.
The untransformed `let` keyword causes problems for older parsers. I understand using `let` instead of `var` ensures each getter function has its own binding for the KEY variable, but the same can be accomplished (with less code) using a `.forEach` callback function, and this way there's no need to worry about generating a unique name for the `key` variable.
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@@ -6,16 +6,15 @@ Object.defineProperty(exports, "__esModule", {
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var _foo = require("foo");
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for (let _key in _foo) {
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if (_key === "default") continue;
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Object.defineProperty(exports, _key, {
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Object.keys(_foo).forEach(function (key) {
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if (key === "default") return;
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Object.defineProperty(exports, key, {
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enumerable: true,
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get: function () {
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return _foo[_key];
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return _foo[key];
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}
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});
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}
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});
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Object.defineProperty(exports, "foo", {
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enumerable: true,
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get: function () {
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@@ -6,21 +6,15 @@ Object.defineProperty(exports, "__esModule", {
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var _bar = require('bar');
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var _loop = function (_key2) {
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if (_key2 === "default") return 'continue';
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Object.defineProperty(exports, _key2, {
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Object.keys(_bar).forEach(function (key) {
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if (key === "default") return;
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Object.defineProperty(exports, key, {
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enumerable: true,
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get: function () {
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return _bar[_key2];
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return _bar[key];
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}
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});
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};
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for (var _key2 in _bar) {
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var _ret = _loop(_key2);
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if (_ret === 'continue') continue;
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}
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});
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var _foo = require('foo');
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@@ -6,18 +6,12 @@ Object.defineProperty(exports, "__esModule", {
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var _mod = require('mod');
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var _loop = function (_key2) {
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if (_key2 === "default") return 'continue';
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Object.defineProperty(exports, _key2, {
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Object.keys(_mod).forEach(function (key) {
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if (key === "default") return;
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Object.defineProperty(exports, key, {
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enumerable: true,
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get: function () {
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return _mod[_key2];
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return _mod[key];
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}
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});
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};
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for (var _key2 in _mod) {
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var _ret = _loop(_key2);
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if (_ret === 'continue') continue;
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}
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});
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