Anatoli Papirovski aefbb1380e No unneeded empty arrays in transform spread (#6763)
* No unneeded empty arrays in transform spread

Since Array.prototype.concat creates a new array from inputs, there's
no need to call it from a new empty array ([].concat()).

* [fixup] simplify detection of new array
2017-11-09 14:51:56 -05:00

37 lines
648 B
JavaScript

var a = 1,
b = 2;
var a = 1,
b = 2;
var a = 1,
b = 2,
c = [3, 4];
var a = 1,
b = 2,
c = [3, 4];
var _ref = [1, 2, 3],
a = _ref[0],
b = _ref[1];
var _ref2 = [1, 2, 3],
a = _ref2[0],
b = _ref2[1];
var _ref3 = [a, b],
a = _ref3[0],
b = _ref3[1];
var _ref4 = [a[1], a[0]];
a[0] = _ref4[0];
a[1] = _ref4[1];
var _ref5 = babelHelpers.toConsumableArray(foo).concat([bar]),
a = _ref5[0],
b = _ref5[1];
var _ref6 = [foo(), bar],
a = _ref6[0],
b = _ref6[1];
var _ref7 = [clazz.foo(), bar],
a = _ref7[0],
b = _ref7[1];
var _ref8 = [clazz.foo, bar],
a = _ref8[0],
b = _ref8[1];