8 lines
173 B
JavaScript
8 lines
173 B
JavaScript
var _ref, _;
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var result = (_ref = (_ = 5, Math.pow(_, 2)), [10, 20, 30, 40, 50].filter(n => {
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var _ref2, _ref3;
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return _ref2 = (_ref3 = _ref, n > _ref3), !_ref2;
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}));
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