8 lines
212 B
JavaScript
8 lines
212 B
JavaScript
var _topic2, _topic8;
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var result = (_topic8 = (_topic2 = 5, Math.pow(_topic2, 2)), [10, 20, 30, 40, 50].filter(n => {
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var _topic5, _topic7;
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return _topic7 = (_topic5 = _topic8, n > _topic5), !_topic7;
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}));
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