Ensure array is always copied during destructure
This commit is contained in:
parent
39d18679e1
commit
a749907bc2
@ -294,10 +294,7 @@ export default function ({ types: t }) {
|
||||
|
||||
if (t.isRestElement(elem)) {
|
||||
elemRef = this.toArray(arrayRef);
|
||||
|
||||
if (i > 0) {
|
||||
elemRef = t.callExpression(t.memberExpression(elemRef, t.identifier("slice")), [t.numericLiteral(i)]);
|
||||
}
|
||||
elemRef = t.callExpression(t.memberExpression(elemRef, t.identifier("slice")), [t.numericLiteral(i)]);
|
||||
|
||||
// set the element to the rest element argument since we've dealt with it
|
||||
// being a rest already
|
||||
|
||||
@ -0,0 +1,9 @@
|
||||
const assign = ([...arr], index, value) => {
|
||||
arr[index] = value;
|
||||
return arr;
|
||||
}
|
||||
|
||||
const arr = [1, 2, 3];
|
||||
assign(arr, 1, 42);
|
||||
|
||||
assert.deepEqual(arr, [1, 2, 3]);
|
||||
Loading…
x
Reference in New Issue
Block a user